-16x^2+110x+80=20

Solution for -16x^2+110x+80=20 equation:

-16x^2+110x+80=20

We move all terms to the left:

-16x^2+110x+80-(20)=0

We add all the numbers together, and all the variables

-16x^2+110x+60=0

a = -16; b = 110; c = +60;
Δ = b2-4ac
Δ = 1102-4·(-16)·60
Δ = 15940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15940}=\sqrt{4*3985}=\sqrt{4}*\sqrt{3985}=2\sqrt{3985}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-2\sqrt{3985}}{2*-16}=\frac{-110-2\sqrt{3985}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+2\sqrt{3985}}{2*-16}=\frac{-110+2\sqrt{3985}}{-32}
$